2cos^2(x)+7cos(x)+3=0

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Solution for 2cos^2(x)+7cos(x)+3=0 equation:


Simplifying
2cos2(x) + 7cos(x) + 3 = 0

Multiply cos2 * x
2cos2x + 7cos(x) + 3 = 0

Multiply cos * x
2cos2x + 7cosx + 3 = 0

Reorder the terms:
3 + 7cosx + 2cos2x = 0

Solving
3 + 7cosx + 2cos2x = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + 7cosx + -3 + 2cos2x = 0 + -3

Reorder the terms:
3 + -3 + 7cosx + 2cos2x = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 7cosx + 2cos2x = 0 + -3
7cosx + 2cos2x = 0 + -3

Combine like terms: 0 + -3 = -3
7cosx + 2cos2x = -3

Reorder the terms:
3 + 7cosx + 2cos2x = -3 + 3

Combine like terms: -3 + 3 = 0
3 + 7cosx + 2cos2x = 0

The solution to this equation could not be determined.

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